EDUCATIONAL USE ONLY

1. Project information

Calculation report

Date31/10/2026

2. Overview of the structure

Structure

The structure with the numbers of the nodes (n), members (m) and supports (S), and the length of each member (mm).

Sections and materialsMembers
RECT 50x100 · C241

2 nodes, 1 members · consequence class CC1, new build · design code Eurocode · Z is the vertical axis · units: kN, kNm, mm.

3. Summary of the results

QuantityMax. valueCombinationWhere
Moment My (strong axis)0.5 kNmULS 6.10b (CC1 new)member b, x = 750 mm
Normal force N (− compression)0.0 kNULS 6.10a (CC1 new)–
Shear force Vz (strong axis)1.3 kNULS 6.10b (CC1 new)member b, x = 0 mm
Vertical reaction1.3 kNULS 6.10b (CC1 new)node A
Displacement (max., incl. between nodes)1.99 mmSLS char.member b, x = 750 mm
Deflection of a member (relative to chord)2.68 mm (L/559)SLS char.member b

Moments, forces and reactions: the governing ULS combination. Displacement: the governing SLS combination (the ULS combinations if there is no SLS combination).

Highest unity check: UC 0.45 in member b (RECT 50x100): deflection (SLS).

4. Nodes, members and supports

Nodes

Nodex (mm)y (mm)z (mm)Support
A000S1
B150000S2

Members

MemberNodesL (mm)SectionMaterialRemarks
bA – B1500RECT 50x100C24sideways supports at 1000

Supports

SupportNodeRestraintSprings
S1Apinned (translations fixed)
S2Bpinned (translations fixed)

5. Loads

Loads: Permanent (G)

Loads: Permanent (G)
TypeOnValue
Line loadmember bX 0.00, Y 0.00, Z -0.54 kN/m

Loads: Variable (Q)

Loads: Variable (Q)
TypeOnValue
Line loadmember bX 0.00, Y 0.00, Z -0.82 kN/m

The self weight of members, walls and slabs is automatic (case SW) and is not drawn. Loads are shown as in the model; combination factors are in the table at the end.

6. Load combinations

Consequence class CC1, new build.

CombinationKindSWGQ
ULS 6.10a (CC1 new)ULS1.221.220.54
ULS 6.10b (CC1 new)ULS1.081.081.35
SLS char.SLS111
ULS 0.9·G favourable (CC1 new)ULS0.90.90
ULS 0.9·G + Variable (Q) (CC1 new)ULS0.90.91.35
ULS γG·G permanent only (CC1 new)ULS1.221.220
ULS 0.9·G + ψ0 variable (CC1 new)ULS0.90.90.54
SLS permanent (G)SLS110
SLS quasi-permanent (G + ψ2·Q)SLS110.3
SLS frequent (G + ψ1·Q)SLS110.5

SW = Self weight; G = Permanent (G); Q = Variable (Q). SW = self weight.

7. Moments, normal forces and shear forces

Bending moment

Maximum 0.5 kNm in member b, x = 750 mm. (ULS 6.10b (CC1 new))

Bending moment

Normal force

Maximum 0.0 kN (− compression) in member , x = 0 mm. (ULS 6.10a (CC1 new))

Normal force

Shear force

Maximum 1.3 kN in member b, x = 0 mm. (ULS 6.10b (CC1 new))

Shear force

Largest section forces per member — ULS 6.10b (CC1 new)

MemberL (mm)|M| max (kNm)N at max |N| (kN)|V| max (kN)
b15000.50.01.3

The 12 members with the largest moment. All members are in the calculation; open a member for the full values.

Support reactions

Largest vertical reaction 1.3 kN at node A. Total vertical reaction 2.6 kN. (ULS 6.10b (CC1 new))

Support reactions

Support reactions (envelope of the ULS combinations)

SupportNodex, y, z (mm)FX (kN)FY (kN)FZ (kN)
S1A0, 0, 00.00.01.3
S2B1500, 0, 00.00.01.3

For every component the value of the largest magnitude over all ULS combinations (sign as in the global axes, Z up), so the horizontal reactions are included. The largest vertical reaction (total 2.6 kN) occurs in ULS 6.10b (CC1 new). Forces in kN; there are no horizontal reactions or support moments.

Vertical support reactions: envelope of the ULS combinations (min / max)

SupportNodeMin (kN)Max (kN)
S1A0.381.28
S2B0.381.28

Deformation

Maximum displacement 1.99 mm at node b. (SLS char.)

Deformation

Deflection and sway check (SLS)

MemberL (mm)δ (mm)LimitLimit (mm)δ / limit
b15002.68L/2506.000.45within the limit

δ is the largest deflection relative to the chord between the member ends (columns: the horizontal sway of the top relative to the bottom, h = height; the bending of the column itself is not part of this check) in SLS char.. Standard limit L/250; set a stricter limit (e.g. L/500 with masonry or a brittle finish) per member. The values are project requirements: check the National Annex.

Results per combination

CombinationM min (kNm)M max (kNm)V min (kN)V max (kN)N min (kN)N max (kN)Vertical reaction (kN): S1 / S2Max. displacement (mm)
ULS 6.10a (CC1 new)0.000.32-0.850.850.000.000.85 / 0.851.62
ULS 6.10b (CC1 new)0.000.48-1.281.280.000.001.28 / 1.282.46
SLS char.0.000.39-1.041.040.000.001.04 / 1.041.99
ULS 0.9·G favourable (CC1 new)0.000.14-0.380.380.000.000.38 / 0.380.73
ULS 0.9·G + Variable (Q) (CC1 new)0.000.45-1.211.210.000.001.21 / 1.212.32
ULS γG·G permanent only (CC1 new)0.000.19-0.510.510.000.000.51 / 0.510.98
ULS 0.9·G + ψ0 variable (CC1 new)0.000.27-0.710.710.000.000.71 / 0.711.36
SLS permanent (G)0.000.16-0.420.420.000.000.42 / 0.420.81
SLS quasi-permanent (G + ψ2·Q)0.000.23-0.610.610.000.000.61 / 0.611.16
SLS frequent (G + ψ1·Q)0.000.27-0.730.730.000.000.73 / 0.731.40

Moment and shear force about the strong axis, section forces at 21 points per member; N − = compression. Displacement: the largest, including between the nodes.

8. Unity checks and calculations

Unity checks

Members coloured by their governing unity check: green up to UC 1.00, red above. The deflection check counts too.

MemberSectionUCGoverning check
bRECT 50x1000.45deflection (SLS)

Member calculations

Detailed calculations of the members with a check (concrete EN 1992-1-1, steel EN 1993-1-1 / AISC 360).

Timber member b — RECT 50x100, C24

NEN-EN 1995-1-1 (Eurocode 5), ultimate limit state. Characteristic strengths from EN 338.

1. Input

Sectionb × h50 × 100 mm
Strength classfm,k, ft,0,k, fc,0,k, fv,kC24: 24, 14.5, 21, 4 N/mm²
StiffnessE0,05, E0,mean7400, 11000 N/mm²
Service classkmod permanent / medium / short1: 0.6 / 0.8 / 0.9 (kdef = 0.6)
Length1500 mm
Lateral restraint pointsunrestrained lengths1000 mm, 500 mm
Load position, ky, kztop, 1, 1

1a. Design values, governing combination (medium-term)

kmod, γMtable 3.1, NB0.8, 1.3
khbending y, bending z, tension1.084, 1.246, 1.084
fm,y,d, fm,z,dkmod kh fm,k / γM16.02, 18.40 N/mm²
ft,0,d, ft,90,d9.68, 0.25 N/mm²
fc,0,d, fc,90,d12.92, 1.54 N/mm²
fv,d2.46 N/mm²

1b. Stability

Stability parameters member

NEN-EN 1995-1-1 6.3.2

System length and buckling lengthsl_sys = L, l_cr = k·L
= l_sys = 1500 mm, l_cr,y = 1500 mm, l_cr,z = 1500 mm
1500 mm
Slenderness λ_y, λ_z [NEN-EN 1995-1-1 (6.21)]l_cr / i, i_y = h/√12, i_z = b/√12
= λ_y = 52, λ_z = 103.9
51.962
Relative slenderness λ_rel,y, λ_rel,z [NEN-EN 1995-1-1 (6.21, 6.22)]λ/π · √(f_c,0,k / E_0,05)
= λ_rel,y = 0.881, λ_rel,z = 1.762
0.8811
Straightness factor β_c [NEN-EN 1995-1-1 (6.29)]solid timber
= β_c = 0.2
0.2
k_y, k_z [NEN-EN 1995-1-1 (6.27, 6.28)]0.5 (1 + β_c (λ_rel − 0.3) + λ_rel²)
= k_y = 0.946, k_z = 2.199
0.94628
k_c,y, k_c,z [NEN-EN 1995-1-1 (6.25, 6.26)]1 / (k + √(k² − λ_rel²))
= k_c,y = 0.774, k_c,z = 0.285
given for every member; the buckling check itself applies under compression
0.77436

2. Results per combination

ULS 6.10a (CC1 new) (medium-term)Bending, x = 750 mm0.24
ULS 6.10b (CC1 new) (medium-term)Bending, x = 750 mm0.36
ULS 0.9·G favourable (CC1 new) (permanent)Bending, x = 750 mm0.14
ULS 0.9·G + Variable (Q) (CC1 new) (medium-term)Bending, x = 750 mm0.34
ULS γG·G permanent only (CC1 new) (permanent)Bending, x = 750 mm0.19
ULS 0.9·G + ψ0 variable (CC1 new) (medium-term)Bending, x = 750 mm0.20

3. Calculation of every combination

ULS 6.10a (CC1 new) 0.24

0.24 Bending x = 750 mm

NEN-EN 1995-1-1 6.1.6 (6.11, 6.12)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.317 kNm / 83.3 cm³ = 3.8
3.8044 N/mm²
Check (6.11)σ_m,y/f_m,y + k_m σ_m,z/f_m,z ≤ 1
= 0 + 0.238 + 0 = 0.238
0.23752
Check (6.12) [k_m = 0.7 (rectangular section)]k_m σ_m,y/f_m,y + σ_m,z/f_m,z ≤ 1
= 0 + 0.166 + 0 = 0.166
0.16627
0.24 Lateral torsional buckling x = 750 mm

NEN-EN 1995-1-1 6.3.3 (6.33)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.317 kNm / 83.3 cm³ = 3.8
3.8044 N/mm²
Effective length l_ef [NEN-EN 1995-1-1 table 6.1 (simply supported, uniform load)]0.9·l + 2h
= l = 1000 mm: l_ef = 1100 mm
1100 mm
Critical bending stress σ_m,crit [NEN-EN 1995-1-1 6.3.3 (6.32)]0.78 b² E_0,05 / (h · l_ef)
= 0.78 · 50² · 7400 / (100 · 1100) = 131.18
131.18 N/mm²
Relative slenderness λ_rel,m [NEN-EN 1995-1-1 (6.30)]√(f_m,k / σ_m,crit)
= √(24 / 131.18) = 0.428
0.42773
Lateral buckling factor k_crit [NEN-EN 1995-1-1 (6.34)]1 (≤ 0.75); 1.56 − 0.75λ (≤ 1.4); 1/λ²
= k_crit = 1
1
Check (6.33)σ_m,d / (k_crit f_m,d) ≤ 1
= 0.238 = 0.238
0.23752
0.15 Shear x = 0 mm

NEN-EN 1995-1-1 6.1.7 (6.13)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Design shear strength f_v,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · f_v,k / γ_M
= 0.8 · 4 / 1.3 = 2.46
2.4615 N/mm²
Shear stress τ_d [NEN-EN 1995-1-1 (6.13, 6.13a)]1.5 V / (k_cr b h), k_cr = 0.67
= 1.5 · 0.845 kN / (0.67 · 50 · 100) = 0.379
0.37854 N/mm²
Check (6.13)τ_d / f_v,d ≤ 1
= 0.379 / 2.46 = 0.154
0.15378

ULS 6.10b (CC1 new) 0.36

0.36 Bending x = 750 mm

NEN-EN 1995-1-1 6.1.6 (6.11, 6.12)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.482 kNm / 83.3 cm³ = 5.78
5.781 N/mm²
Check (6.11)σ_m,y/f_m,y + k_m σ_m,z/f_m,z ≤ 1
= 0 + 0.361 + 0 = 0.361
0.36093
Check (6.12) [k_m = 0.7 (rectangular section)]k_m σ_m,y/f_m,y + σ_m,z/f_m,z ≤ 1
= 0 + 0.253 + 0 = 0.253
0.25265
0.36 Lateral torsional buckling x = 750 mm

NEN-EN 1995-1-1 6.3.3 (6.33)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.482 kNm / 83.3 cm³ = 5.78
5.781 N/mm²
Effective length l_ef [NEN-EN 1995-1-1 table 6.1 (simply supported, uniform load)]0.9·l + 2h
= l = 1000 mm: l_ef = 1100 mm
1100 mm
Critical bending stress σ_m,crit [NEN-EN 1995-1-1 6.3.3 (6.32)]0.78 b² E_0,05 / (h · l_ef)
= 0.78 · 50² · 7400 / (100 · 1100) = 131.18
131.18 N/mm²
Relative slenderness λ_rel,m [NEN-EN 1995-1-1 (6.30)]√(f_m,k / σ_m,crit)
= √(24 / 131.18) = 0.428
0.42773
Lateral buckling factor k_crit [NEN-EN 1995-1-1 (6.34)]1 (≤ 0.75); 1.56 − 0.75λ (≤ 1.4); 1/λ²
= k_crit = 1
1
Check (6.33)σ_m,d / (k_crit f_m,d) ≤ 1
= 0.361 = 0.361
0.36093
0.23 Shear x = 0 mm

NEN-EN 1995-1-1 6.1.7 (6.13)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Design shear strength f_v,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · f_v,k / γ_M
= 0.8 · 4 / 1.3 = 2.46
2.4615 N/mm²
Shear stress τ_d [NEN-EN 1995-1-1 (6.13, 6.13a)]1.5 V / (k_cr b h), k_cr = 0.67
= 1.5 · 1.285 kN / (0.67 · 50 · 100) = 0.575
0.57522 N/mm²
Check (6.13)τ_d / f_v,d ≤ 1
= 0.575 / 2.46 = 0.234
0.23368

ULS 0.9·G favourable (CC1 new) 0.14

0.14 Bending x = 750 mm

NEN-EN 1995-1-1 6.1.6 (6.11, 6.12)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, permanent
= k_mod = 0.6
0.6
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.6 · 1.084 · 24 / 1.3 = 12.01
12.013 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.142 kNm / 83.3 cm³ = 1.7
1.704 N/mm²
Check (6.11)σ_m,y/f_m,y + k_m σ_m,z/f_m,z ≤ 1
= 0 + 0.142 + 0 = 0.142
0.14185
Check (6.12) [k_m = 0.7 (rectangular section)]k_m σ_m,y/f_m,y + σ_m,z/f_m,z ≤ 1
= 0 + 0.099 + 0 = 0.099
0.099298
0.14 Lateral torsional buckling x = 750 mm

NEN-EN 1995-1-1 6.3.3 (6.33)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, permanent
= k_mod = 0.6
0.6
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.6 · 1.084 · 24 / 1.3 = 12.01
12.013 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.142 kNm / 83.3 cm³ = 1.7
1.704 N/mm²
Effective length l_ef [NEN-EN 1995-1-1 table 6.1 (simply supported, uniform load)]0.9·l + 2h
= l = 1000 mm: l_ef = 1100 mm
1100 mm
Critical bending stress σ_m,crit [NEN-EN 1995-1-1 6.3.3 (6.32)]0.78 b² E_0,05 / (h · l_ef)
= 0.78 · 50² · 7400 / (100 · 1100) = 131.18
131.18 N/mm²
Relative slenderness λ_rel,m [NEN-EN 1995-1-1 (6.30)]√(f_m,k / σ_m,crit)
= √(24 / 131.18) = 0.428
0.42773
Lateral buckling factor k_crit [NEN-EN 1995-1-1 (6.34)]1 (≤ 0.75); 1.56 − 0.75λ (≤ 1.4); 1/λ²
= k_crit = 1
1
Check (6.33)σ_m,d / (k_crit f_m,d) ≤ 1
= 0.142 = 0.142
0.14185
0.09 Shear x = 0 mm

NEN-EN 1995-1-1 6.1.7 (6.13)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, permanent
= k_mod = 0.6
0.6
Design shear strength f_v,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · f_v,k / γ_M
= 0.6 · 4 / 1.3 = 1.85
1.8462 N/mm²
Shear stress τ_d [NEN-EN 1995-1-1 (6.13, 6.13a)]1.5 V / (k_cr b h), k_cr = 0.67
= 1.5 · 0.379 kN / (0.67 · 50 · 100) = 0.17
0.16956 N/mm²
Check (6.13)τ_d / f_v,d ≤ 1
= 0.17 / 1.85 = 0.092
0.091843

ULS 0.9·G + Variable (Q) (CC1 new) 0.34

0.34 Bending x = 750 mm

NEN-EN 1995-1-1 6.1.6 (6.11, 6.12)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.453 kNm / 83.3 cm³ = 5.44
5.4402 N/mm²
Check (6.11)σ_m,y/f_m,y + k_m σ_m,z/f_m,z ≤ 1
= 0 + 0.34 + 0 = 0.34
0.33965
Check (6.12) [k_m = 0.7 (rectangular section)]k_m σ_m,y/f_m,y + σ_m,z/f_m,z ≤ 1
= 0 + 0.238 + 0 = 0.238
0.23776
0.34 Lateral torsional buckling x = 750 mm

NEN-EN 1995-1-1 6.3.3 (6.33)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.453 kNm / 83.3 cm³ = 5.44
5.4402 N/mm²
Effective length l_ef [NEN-EN 1995-1-1 table 6.1 (simply supported, uniform load)]0.9·l + 2h
= l = 1000 mm: l_ef = 1100 mm
1100 mm
Critical bending stress σ_m,crit [NEN-EN 1995-1-1 6.3.3 (6.32)]0.78 b² E_0,05 / (h · l_ef)
= 0.78 · 50² · 7400 / (100 · 1100) = 131.18
131.18 N/mm²
Relative slenderness λ_rel,m [NEN-EN 1995-1-1 (6.30)]√(f_m,k / σ_m,crit)
= √(24 / 131.18) = 0.428
0.42773
Lateral buckling factor k_crit [NEN-EN 1995-1-1 (6.34)]1 (≤ 0.75); 1.56 − 0.75λ (≤ 1.4); 1/λ²
= k_crit = 1
1
Check (6.33)σ_m,d / (k_crit f_m,d) ≤ 1
= 0.34 = 0.34
0.33965
0.22 Shear x = 0 mm

NEN-EN 1995-1-1 6.1.7 (6.13)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Design shear strength f_v,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · f_v,k / γ_M
= 0.8 · 4 / 1.3 = 2.46
2.4615 N/mm²
Shear stress τ_d [NEN-EN 1995-1-1 (6.13, 6.13a)]1.5 V / (k_cr b h), k_cr = 0.67
= 1.5 · 1.209 kN / (0.67 · 50 · 100) = 0.541
0.54131 N/mm²
Check (6.13)τ_d / f_v,d ≤ 1
= 0.541 / 2.46 = 0.22
0.21991

ULS γG·G permanent only (CC1 new) 0.19

0.19 Bending x = 750 mm

NEN-EN 1995-1-1 6.1.6 (6.11, 6.12)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, permanent
= k_mod = 0.6
0.6
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.6 · 1.084 · 24 / 1.3 = 12.01
12.013 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.192 kNm / 83.3 cm³ = 2.31
2.3099 N/mm²
Check (6.11)σ_m,y/f_m,y + k_m σ_m,z/f_m,z ≤ 1
= 0 + 0.192 + 0 = 0.192
0.19229
Check (6.12) [k_m = 0.7 (rectangular section)]k_m σ_m,y/f_m,y + σ_m,z/f_m,z ≤ 1
= 0 + 0.135 + 0 = 0.135
0.1346
0.19 Lateral torsional buckling x = 750 mm

NEN-EN 1995-1-1 6.3.3 (6.33)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, permanent
= k_mod = 0.6
0.6
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.6 · 1.084 · 24 / 1.3 = 12.01
12.013 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.192 kNm / 83.3 cm³ = 2.31
2.3099 N/mm²
Effective length l_ef [NEN-EN 1995-1-1 table 6.1 (simply supported, uniform load)]0.9·l + 2h
= l = 1000 mm: l_ef = 1100 mm
1100 mm
Critical bending stress σ_m,crit [NEN-EN 1995-1-1 6.3.3 (6.32)]0.78 b² E_0,05 / (h · l_ef)
= 0.78 · 50² · 7400 / (100 · 1100) = 131.18
131.18 N/mm²
Relative slenderness λ_rel,m [NEN-EN 1995-1-1 (6.30)]√(f_m,k / σ_m,crit)
= √(24 / 131.18) = 0.428
0.42773
Lateral buckling factor k_crit [NEN-EN 1995-1-1 (6.34)]1 (≤ 0.75); 1.56 − 0.75λ (≤ 1.4); 1/λ²
= k_crit = 1
1
Check (6.33)σ_m,d / (k_crit f_m,d) ≤ 1
= 0.192 = 0.192
0.19229
0.12 Shear x = 0 mm

NEN-EN 1995-1-1 6.1.7 (6.13)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, permanent
= k_mod = 0.6
0.6
Design shear strength f_v,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · f_v,k / γ_M
= 0.6 · 4 / 1.3 = 1.85
1.8462 N/mm²
Shear stress τ_d [NEN-EN 1995-1-1 (6.13, 6.13a)]1.5 V / (k_cr b h), k_cr = 0.67
= 1.5 · 0.513 kN / (0.67 · 50 · 100) = 0.23
0.22984 N/mm²
Check (6.13)τ_d / f_v,d ≤ 1
= 0.23 / 1.85 = 0.124
0.1245

ULS 0.9·G + ψ0 variable (CC1 new) 0.20

0.20 Bending x = 750 mm

NEN-EN 1995-1-1 6.1.6 (6.11, 6.12)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.267 kNm / 83.3 cm³ = 3.2
3.1985 N/mm²
Check (6.11)σ_m,y/f_m,y + k_m σ_m,z/f_m,z ≤ 1
= 0 + 0.2 + 0 = 0.2
0.1997
Check (6.12) [k_m = 0.7 (rectangular section)]k_m σ_m,y/f_m,y + σ_m,z/f_m,z ≤ 1
= 0 + 0.14 + 0 = 0.14
0.13979
0.20 Lateral torsional buckling x = 750 mm

NEN-EN 1995-1-1 6.3.3 (6.33)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Partial factor γ_M [NB table NA.2]solid timber
= γ_M = 1.3
1.3
Size factor k_h [NEN-EN 1995-1-1 3.2(3)]min(1.3; (150/h)^0.2)
= h = 100 mm: k_h,m,y = 1.084, tension k_h,t = 1.084
1.0845
Design bending strength f_m,y,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · k_h · f_m,k / γ_M
= 0.8 · 1.084 · 24 / 1.3 = 16.02
16.017 N/mm²
Bending stress σ_m,y,dM_y / W_y
= 0.267 kNm / 83.3 cm³ = 3.2
3.1985 N/mm²
Effective length l_ef [NEN-EN 1995-1-1 table 6.1 (simply supported, uniform load)]0.9·l + 2h
= l = 1000 mm: l_ef = 1100 mm
1100 mm
Critical bending stress σ_m,crit [NEN-EN 1995-1-1 6.3.3 (6.32)]0.78 b² E_0,05 / (h · l_ef)
= 0.78 · 50² · 7400 / (100 · 1100) = 131.18
131.18 N/mm²
Relative slenderness λ_rel,m [NEN-EN 1995-1-1 (6.30)]√(f_m,k / σ_m,crit)
= √(24 / 131.18) = 0.428
0.42773
Lateral buckling factor k_crit [NEN-EN 1995-1-1 (6.34)]1 (≤ 0.75); 1.56 − 0.75λ (≤ 1.4); 1/λ²
= k_crit = 1
1
Check (6.33)σ_m,d / (k_crit f_m,d) ≤ 1
= 0.2 = 0.2
0.1997
0.13 Shear x = 0 mm

NEN-EN 1995-1-1 6.1.7 (6.13)

Modification factor k_mod [NEN-EN 1995-1-1 3.1.3]table 3.1, service class 1, medium-term
= k_mod = 0.8
0.8
Design shear strength f_v,d [NEN-EN 1995-1-1 2.4.1(1)]k_mod · f_v,k / γ_M
= 0.8 · 4 / 1.3 = 2.46
2.4615 N/mm²
Shear stress τ_d [NEN-EN 1995-1-1 (6.13, 6.13a)]1.5 V / (k_cr b h), k_cr = 0.67
= 1.5 · 0.711 kN / (0.67 · 50 · 100) = 0.318
0.31826 N/mm²
Check (6.13)τ_d / f_v,d ≤ 1
= 0.318 / 2.46 = 0.129
0.12929

Serviceability results

Deflection of the member relative to the chord between its ends, per serviceability combination. Final deflection with creep: quasi-permanent and permanent combinations all × (1 + k), characteristic combination G × (1 + k) + Q × (1 + ψ2·k).

CombinationDeflection (mm)Final incl. creep (mm)Reaction at the start (kN)
SLS char.1.992.681.04
SLS permanent (G)0.811.290.42
SLS quasi-permanent (G + ψ2·Q)1.161.860.61
SLS frequent (G + ψ1·Q)1.40–0.73

Deflection checks (NEN-EN 1995-1-1 NB)

CheckValue (mm)Limit (mm)Ratio
w1 permanent load, instantaneous0.81
w2 creep (final − instantaneous)0.70
winst instantaneous, G + Q1.996.00 (L/250)0.33
wbij = wfin − w11.884.50 (L/333)0.42
wnet,fin final, incl. creep2.686.00 (L/250)0.45

Conclusion

Maximum unity check = 0.36 — ULS 6.10b (CC1 new): Bending, x = 750 mm.

Connections and fire are not checked. Bearing stress and notches are only checked where you enter a bearing length or a notch; the support reaction is the shear force at the end of the member, or the sum of both sides where another member continues over the support. Load-duration classes follow the load case type (G permanent, Q medium-term, wind short-term).

Calculation steps are in SI units (mm, N, kN, kNm, N/mm²).

For training, testing and educational use; not for the design of real structures.

For training, testing and educational use only. Not for design of real structures. Results are unverified. THE SOFTWARE IS PROVIDED 'AS IS', WITHOUT WARRANTY OF ANY KIND. Not a substitute for review by a licensed Professional Engineer (PE/SE) or equivalent.